"

Answer Key 1.3

  1. \(\begin{array}{l}
    \\ \\ \\
    -6 \cdot -\dfrac{4}{1}\\ \\
    -6 \cdot -4 \\
    24
    \end{array}\)
  2. \((-1)^3=-1\)
  3. \(\begin{array}{l}
    \\ \\
    3+8 \div 4 \\
    3+2 \\
    5
    \end{array}\)
  4. \(\begin{array}{l}
    \\ \\
    5(1)\cdot 36 \\
    5\cdot 36 \\
    180
    \end{array}\)
  5. \(\begin{array}{l}
    \\ \\
    8 \div 4\cdot 2 \\
    2 \cdot 2 \\
    4
    \end{array}\)
  6. \(2+6=8\)
  7. \(\begin{array}{l}
    \\ \\ \\
    \left[-9-(2-5)\right] \div -6 \\
    \left[-9-(-3)\right]\div -6 \\
    \left[-6\right] \div -6 \\
    1
    \end{array}\)
  8. \(\begin{array}{l}
    \\ \\
    (-2 \cdot 8\cdot 2) \div (-4) \\
    -32 \div -4 \\
    8
    \end{array}\)
  9. \(\begin{array}{l}
    \\ \\ \\
    -6 + (-6)^2\div 3 \\
    -6 + 36 \div 3 \\
    -6 + 12 \\
    6
    \end{array}\)
  10. \(\begin{array}{l}
    \\ \\
    -12 \div [-2-2+6] \\
    -12 \div 2 \\
    -6
    \end{array}\)
  11. \(\begin{array}{l}
    \\ \\ \\
    4-2|9-16| \\
    4-2(7) \\
    4-14 \\
    -10
    \end{array}\)
  12. \(\begin{array}{l}
    \\ \\
    -16 \div 4 -5 \\
    -4-5 \\
    -9
    \end{array}\)
  13. \(\begin{array}{l}
    \\ \\
    (-1+5)(5) \\
    4(5) \\
    20
    \end{array}\)
  14. \(\begin{array}{l}
    \\ \\ \\ \\
    -3-\{3-[-3(6)+2]\} \\
    -3-\{3-[-18+2]\} \\
    -3-\{3-[-16]\} \\
    -3-\{19\} \\
    -22
    \end{array}\)
  15. \(\begin{array}{l}
    \\ \\ \\ \\
    \left[2+4|7+4| \right] \div \left[8+15\right] \\
    \left[2+4(11)\right] \div 23 \\
    2+44 \div 23 \\
    46\div 23 \\
    2
    \end{array}\)
  16. \(\begin{array}{l}
    \\ \\
    -4-\left[2-24-4-22-10\right] \\
    -4-\left[-58\right] \\
    54
    \end{array}\)
  17. \(\begin{array}{l}
    \\ \\ \\
    \left[12+2+6\right](-5+ |-3|) \\
    (20)(-5+3) \\
    (20)(-2) \\
    -40
    \end{array}\)
  18. \(\begin{array}{l}
    \\ \\ \\ \\
    -6+3-6\left[-2-(-4)\right] \\
    -3-6\left[-2+4\right] \\
    -3-6\left[2\right] \\
    -3-12 \\
    -15
    \end{array}\)
  19. \(\begin{array}{l}
    \\ \\ \\ \\ \\
    \dfrac{-15}{2--1-6-[-1+3]} \\ \\
    -15 \div (-3-[2]) \\
    -15 \div (-5) \\
    3
    \end{array}\)
  20. \(\begin{array}{l}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    \dfrac{25+25}{|16-32| - 6} \\ \\
    \dfrac{50}{|-16|-6} \\ \\
    \dfrac{50}{16-6} \\ \\
    \dfrac{50}{10} \\ \\
    5
    \end{array}\)
  21. \(\begin{array}{l}
    \\ \\ \\ \\ \\ \\ \\ \\
    \dfrac{-48-4-4-[-4+3]}{(16+9)\div 5} \\ \\
    \dfrac{-56-[-1]}{25\div 5} \\ \\
    \dfrac{-55}{5} \\ \\
    -11
    \end{array}\)
  22. \(\begin{array}{l}
    \\ \\ \\ \\ \\
    \dfrac{-18-(-3)}{1-(-1)+3} \\ \\
    -\dfrac{15}{5} \\ \\
    -3
    \end{array}\)
  23. \(\begin{array}{l}
    \\ \\ \\ \\ \\
    \dfrac{8+4}{-24-4-[-25]} \\ \\
    -\dfrac{12}{3} \\ \\
    -4
    \end{array}\)
  24. \(\begin{array}{l}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    \dfrac{13+9-12+1-[-10+6]}{\{9 \div [16-9(1)-8]\}+12} \\ \\
    \dfrac{11-[-4]}{\{9\div [-1]\}+12} \\ \\
    \dfrac{15}{-9+12} \\ \\
    \dfrac{15}{3} \\ \\
    5
    \end{array}\)

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.