"

Answer Key 1.2

  1. \(\dfrac{42}{12}\div\dfrac{6}{6} = \dfrac{7}{2}\)
  2. \(\dfrac{25}{20}\div\dfrac{5}{5} = \dfrac{5}{4}\)
  3. \(\dfrac{35}{25}\div\dfrac{5}{5} = \dfrac{7}{5}\)
  4. \(\dfrac{24}{8}\div\dfrac{8}{8} = 3\)
  5. \(\dfrac{54}{36}\div\dfrac{9}{9} = \dfrac{6}{4}\div\dfrac{2}{2} = \dfrac{3}{2}\)
  6. \(\dfrac{30}{24}\div \dfrac{6}{6} = \dfrac{5}{4}\)
  7. \(\dfrac{45}{36}\div \dfrac{9}{9} = \dfrac{5}{4}\)
  8. \(\dfrac{36}{27}\div\dfrac{9}{9} = \dfrac{4}{3}\)
  9. \(\dfrac{27}{18}\div\dfrac{9}{9} = \dfrac{3}{2}\)
  10. \(\dfrac{48}{18}\div\dfrac{6}{6} = \dfrac{8}{3}\)
  11. \(\dfrac{40}{16}\div\dfrac{8}{8} = \dfrac{5}{2}\)
  12. \(\dfrac{48}{42}\div \dfrac{6}{6} = \dfrac{8}{7}\)
  13. \(\dfrac{63}{18}\div\dfrac{9}{9} = \dfrac{7}{2}\)
  14. \(\dfrac{16}{12}\div\dfrac{4}{4} = \dfrac{4}{3}\)
  15. \(\dfrac{80}{60} \div\dfrac{20}{20} = \dfrac{4}{3}\)
  16. \(\dfrac{72}{48}\div\dfrac{12}{12} = \dfrac{6}{4}\div\dfrac{2}{2} = \dfrac{3}{2}\)
  17. \(\dfrac{72}{60}\div\dfrac{12}{12} = \dfrac{6}{5}\)
  18. \(\dfrac{126}{108}\div\dfrac{9}{9} = \dfrac{14}{12}\div\dfrac{2}{2} = \dfrac{7}{6}\)
  19. \(\cancel{9} \cdot \dfrac{8}{\cancel{9}} =  8\)
  20. \(\cancel{-2}-1\cdot -\dfrac{5}{\cancel{6}3}=\dfrac{5}{3}\)
  21. \(2 \cdot -\dfrac{2}{9} = -\dfrac{4}{9}\)
  22. \(-2\cdot \dfrac{1}{3}=-\dfrac{2}{3}\)
  23. \(\cancel{-2}-1\cdot \dfrac{13}{\cancel{8}4}=-\dfrac{13}{4}\)
  24. \(\dfrac{3}{2} \cdot \dfrac{1}{2} = \dfrac {3}{4}\)
  25. \(-\dfrac{\cancel{6}3}{5}\cdot -\dfrac{11}{\cancel{8}4}=\dfrac{33}{20}\)
  26. \(-\dfrac{3}{7} \cdot -\dfrac{11}{8} = \dfrac{33}{56}\)
  27. \(\cancel{8}4 \cdot \dfrac{1}{\cancel{2}1} = 4\)
  28. \(-2 \cdot -\dfrac{9}{7} = \dfrac{18}{7}\)
  29. \(\dfrac{\cancel{2}1}{\cancel{3}1} \cdot \dfrac{\cancel{3}1}{\cancel{4}2} = \dfrac {1}{2}\)
  30. \(-\dfrac{17}{\cancel{9}3} \cdot -\dfrac{\cancel{3}1}{5} = \dfrac{17}{15}\)
  31. \(\cancel{2}1 \cdot \dfrac{3}{\cancel{2}1} = 3\)
  32. \(\dfrac{17}{\cancel{9}3} \cdot -\dfrac{\cancel{3}1}{5} = -\dfrac{17}{15}\)
  33. \(\dfrac{1}{2} \cdot -\dfrac{7}{5} = -\dfrac{7}{10}\)
  34. \(\dfrac{1}{2} \cdot \dfrac{5}{7} = \dfrac{5}{14}\)
  35. \(\dfrac{\cancel{5}1}{2} \cdot -\dfrac{0}{\cancel{5}1} = -\dfrac{0}{2}\text{ or }0\)
  36. \(\underbrace{\dfrac{6}{0}}_{\text{undefined}} \cdot \hspace{0.25in}\dfrac{6}{7} = \text{no solution}\)
  37. \(-2 \cdot \dfrac{4}{7} = -\dfrac{8}{7}\)
  38. \(-\dfrac{\cancel{12}4}{7} \cdot -\dfrac{5}{\cancel{9}3} = \dfrac{20}{21}\)
  39. \(-\dfrac{1}{9} \cdot -\dfrac{2}{1} = \dfrac{2}{9}\)
  40. \(-2 \cdot -\dfrac{2}{3} = \dfrac{4}{3}\)
  41. \(-\dfrac{3}{2} \cdot \dfrac{7}{13} = -\dfrac{21}{26}\)
  42. \(\dfrac{5}{3} \cdot \dfrac{5}{7} = \dfrac{25}{21}\)
  43. \(-1 \cdot \dfrac{3}{2} = -\dfrac{3}{2}\)
  44. \(\dfrac{\cancel{10}5}{9} \cdot -\dfrac{1}{\cancel{6}3} = -\dfrac{5}{27}\)
  45. \(\dfrac{8}{9} \cdot \dfrac{5}{1} = \dfrac{40}{9}\)
  46. \(\dfrac{1}{\cancel{6}2} \cdot -\dfrac{\cancel{3}1}{5} = -\dfrac{1}{10}\)
  47. \(-\dfrac{9}{7} \cdot \dfrac{5}{1} = -\dfrac{45}{7}\)
  48. \(-\dfrac{13}{\cancel{8}1} \cdot -\dfrac{\cancel{8}1}{15} = \dfrac{13}{15}\)
  49. \(-\dfrac{2}{9} \cdot -\dfrac{2}{3} = \dfrac{4}{27}\)
  50. \(-\dfrac{4}{5} \cdot -\dfrac{8}{13} = \dfrac{32}{65}\)
  51. \(\dfrac{1}{\cancel{10}5} \cdot \dfrac{\cancel{2}1}{3} = \dfrac{1}{15}\)
  52. \(\dfrac{\cancel{5}1}{\cancel{3}1} \cdot \dfrac{\cancel{3}1}{\cancel{5}1} = 1\)
  53. \(\dfrac{1}{3}-\dfrac{4}{3} = -\dfrac{3}{3}\text{ or }-1\)
  54. \(\dfrac{1}{7}-\dfrac{11}{7} = -\dfrac{10}{7}\)
  55. \(\dfrac{3}{7} - \dfrac{1}{7} = \dfrac{2}{7}\)
  56. \(\dfrac{1}{3} + \dfrac{5}{3} = \dfrac{6}{3}\text{ or }2\)
  57. \(\dfrac{11}{6} + \dfrac{7}{6} = \dfrac{18}{6}\text{ or }3\)
  58. \( -2 - \dfrac{15}{8} \Rightarrow -\dfrac{16}{8} - \dfrac{15}{8} = -\dfrac{31}{8}\)
  59. \(\dfrac{3}{5}+ \dfrac{5}{4} \Rightarrow \dfrac{12}{20} + \dfrac{25}{20} = \dfrac {37}{20}\)
  60. \(-1- \dfrac{2}{3} \Rightarrow -\dfrac{3}{3} - \dfrac{2}{3} = -\dfrac{5}{3}\)
  61. \(\dfrac{2}{5}+ \dfrac{5}{4} \Rightarrow \dfrac{8}{20} + \dfrac{25}{20} = \dfrac {33}{20}\)
  62. \(\dfrac{12}{7} - \dfrac{9}{7} = \dfrac{3}{7}\)
  63. \(\dfrac{9}{8}- \dfrac{2}{7} \Rightarrow \dfrac {63}{56} - \dfrac{16}{56} = \dfrac {47}{56}\)
  64. \(-2+ \dfrac{5}{6} \Rightarrow -\dfrac{12}{6} + \dfrac{5}{6} = -\dfrac{7}{6}\)
  65. \(1-\dfrac{1}{3} \Rightarrow \dfrac{3}{3} - \dfrac{1}{3} = \dfrac{2}{3}\)
  66. \(\dfrac{1}{2} - \dfrac{11}{6} \Rightarrow \dfrac{3}{6} - \dfrac {11}{6} = -\dfrac{8}{6} \text{ or } -\dfrac{4}{3}\)
  67. \(-\dfrac{1}{2} + \dfrac{3}{2} = \dfrac{2}{2}\text{ or }1\)
  68. \(\dfrac{11}{8} - \dfrac{1}{22} \Rightarrow \dfrac{121}{88} - \dfrac{4}{88} = \dfrac{117}{88}\)
  69. \(\dfrac{1}{5} + \dfrac{3}{4} \Rightarrow \dfrac{4}{20} + \dfrac {15}{20} = \dfrac {19}{20}\)
  70. \(\dfrac{6}{5} - \dfrac{8}{5} = -\dfrac{2}{5}\)

License

Icon for the Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License

Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

Share This Book