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Answer Key 5.5

  1. \(\left\{
    \begin{array}{rrrrr}
    d&+&q&=&103 \\
    10d&+&25q&=&1525
    \end{array}
    \right.\)
  2. \(\left\{
    \begin{array}{rrrrr}
    n&+&f&=&34 \\
    5n&+&50f&=&1340
    \end{array}
    \right.\)
  3. \(\left\{
    \begin{array}{rrrrr}
    A&+&C&=&578 \\
    2A&+&1.5C&=&985
    \end{array}
    \right.\)
  4. \(\left\{
    \begin{array}{rrrrr}
    d&+&q&=&21 \\
    10d&+&25q&=&390
    \end{array}
    \right.\)
  5. \(\left\{
    \begin{array}{rrrrr}
    5n&+&10d&=&225 \\
    &&d&=&2n
    \end{array}
    \right. \)
  6. \(\left\{
    \begin{array}{rrrrrrr}
    25q&+&50f&=&375&& \\
    &&q&=&f&+&3
    \end{array}
    \right. \)
  7. \(\left\{
    \begin{array}{rrrrr}
    I_{9.5}&+&I_{11}&=&10000\phantom{.00} \\
    0.095I_{9.5}&+&0.11I_{11}&=&1038.50
    \end{array}
    \right. \)
  8. \(7000(r)+9000(r+0.02)=900\)
  9. \(1600(r)+2400(2r)=256\)
  10. \(3000(r)+4500(r-0.02)=435\)
  11. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &N&+&C&=&203 \\
    &2N&+&1.25C&=&310 \\ \\
    &(N&+&C&=&\phantom{-}203)(-2) \\
    &-2N&-&2.00C&=&-406 \\
    +&2N&+&1.25C&=&\phantom{-}310 \\
    \hline
    &&&\dfrac{-0.75C}{-0.75}&=&\dfrac{-96}{-0.75} \\ \\
    &&&C&=&128 \\ \\
    &&&N&=&203-C \\
    &&&N&=&203-128 \\
    &&&N&=&75
    \end{array}\)
  12. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &d&+&b&=&131 \\
    &2.50d&+&2.75b&=&342 \\ \\
    &(d&+&b&=&131)(-2.5) \\
    &-2.50d&-&2.50b&=&-327.5 \\
    +&2.50d&+&2.75b&=&\phantom{-}342 \\
    \hline
    &&&\dfrac{0.25b}{0.25}&=&\dfrac{14.5}{0.25} \\ \\
    &&&b&=&58 \\ \\
    &&&d&=&131-b \\
    &&&d&=&131-58 \\
    &&&d&=&73
    \end{array}\)
  13. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &d&+&q&=&\phantom{0}27 \\
    &10d&+&25q&=&495 \\ \\
    &(d&+&q&=&\phantom{-0}27)(-10) \\
    &-10d&-&10q&=&-270 \\
    +&10d&+&25q&=&\phantom{-}495 \\
    \hline
    &&&\dfrac{15q}{15}&=&\dfrac{225}{15} \\ \\
    &&&q&=&15 \\ \\
    &&&d&=&27-q \\
    &&&d&=&27-15 \\
    &&&d&=&12
    \end{array}\)
  14. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &d&+&n&=&18 \\
    &10d&+&5n&=&115 \\ \\
    &(d&+&n&=&18)(-5) \\
    &-5d&-&5n&=&-90 \\
    +&10d&+&5n&=&115 \\
    \hline
    &&&\dfrac{5d}{5}&=&\dfrac{25}{5} \\ \\
    &&&d&=&5 \\ \\
    &&&n&=&18-d \\
    &&&n&=&18-5 \\
    &&&n&=&13
    \end{array}\)
  15. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &S_{25}&+&S_{20}&=&\phantom{0}40 \\
    &25S_{25}&+&20S_{20}&=&960 \\ \\
    &(S_{25}&+&S_{20}&=&40)(-20) \\
    &-20S_{25}&-&20S_{20}&=&-800 \\
    +&25S_{25}&+&20S_{20}&=&\phantom{-}960 \\
    \hline
    &&&\dfrac{5S_{25}}{5}&=&\dfrac{160}{5} \\ \\
    &&&S_{25}&=&32 \\ \\
    &&&S_{20}&=&40-S_{25} \\
    &&&S_{20}&=&40-32 \\
    &&&S_{20}&=&8
    \end{array}\)
  16. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &S_{15}&+&S_{25}&=&\phantom{0}15 \\
    &15S_{15}&+&25S_{25}&=&315 \\ \\
    &(S_{15}&+&S_{25}&=&15)(-15) \\
    &-15S_{15}&-&15S_{25}&=&-225 \\
    +&15S_{15}&+&25S_{25}&=&\phantom{-}315 \\
    \hline
    &&&\dfrac{10S_{25}}{10}&=&\dfrac{90}{10} \\ \\
    &&&S_{25}&=&9 \\ \\
    &&&S_{15}&=&15-S_{25} \\
    &&&S_{15}&=&15-9 \\
    &&&S_{15}&=&6
    \end{array}\)
  17. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &I_{12}&+&I_{13}&=&27000 \\
    &0.12I_{12}&+&0.13I_{13}&=&\phantom{0}3385 \\ \\
    &(I_{12}&+&I_{13}&=&27000)(-0.12) \\
    &-0.12I_{12}&-&0.12I_{13}&=&-3240 \\
    +&0.12I_{12}&+&0.13I_{13}&=&\phantom{-}3385 \\
    \hline
    &&&\dfrac{0.01I_{13}}{0.01}&=&\dfrac{145}{0.01} \\ \\
    &&&I_{13}&=&14500 \\ \\
    &&&I_{12}&=&27000-I_{13} \\
    &&&I_{12}&=&27000-14500 \\
    &&&I_{12}&=&12500
    \end{array}\)
  18. \(\begin{array}{rrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &I_5&+&I_{7.5}&=&50000 \\
    &0.05I_5&+&0.075I_{7.5}&=&3250 \\ \\
    &(I_5&+&I_{7.5}&=&50000)(-0.05) \\
    &-0.05I_5&-&0.05I_{7.5}&=&-2500 \\
    +&0.05I_5&+&0.075I_{7.5}&=&\phantom{-}3250 \\
    \hline
    &&&\dfrac{0.025I_{7.5}}{0.025}&=&\dfrac{750}{0.025} \\ \\
    &&&I_{7.5}&=&30000 \\ \\
    &&&I_5&=&50000-I_{7.5} \\
    &&&I_5&=&50000-30000 \\
    &&&I_5&=&20000
    \end{array}\)
  19. \(\begin{array}{rrrrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &&10d&+&25q&=&605&& \\
    &&&&d&=&q&-&6 \\ \\
    10(q&-&6)&+&25q&=&605&& \\
    10q&-&60&+&25q&=&605&& \\
    &+&60&&&&+60&& \\
    \hline
    &&&&\dfrac{35q}{35}&=&\dfrac{665}{35}&& \\ \\
    &&&&q&=&19&& \\ \\
    &&&&d&=&q&-&6 \\
    &&&&d&=&19&-&6 \\
    &&&&d&=&13&& \\
    \end{array}\)
  20. \(\begin{array}{rrrrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &&5n&+&10d&=&275&& \\
    &&&&d&=&2n&-&10 \\ \\
    5n&+&10(2n&-&10)&=&275&& \\
    5n&+&20n&-&100&=&275&& \\
    &&&+&100&&+100&& \\
    \hline
    &&&&\dfrac{25n}{25}&=&\dfrac{375}{25}&& \\ \\
    &&&&n&=&15&& \\ \\
    &&&&d&=&2n&-&10 \\
    &&&&d&=&2(15)&-&10 \\
    &&&&d&=&30&-&10 \\
    &&&&d&=&20&&
    \end{array}\)
  21. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\
    3000r&+&24000(r&-&0.04)&=&2010 \\
    3000r&+&24000r&-&960&=&2010 \\
    &&&+&960&&+960 \\
    \hline
    &&&&\dfrac{27000r}{27000}&=&\dfrac{2970}{27000} \\ \\
    &&&&r&=&0.11=11\% \\
    &&0.11&-&0.04&=&0.07=7\% \\
    \end{array}\)
  22. \(\begin{array}{rrrrcrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\
    5000r&+&11000\left(\dfrac{2}{3}r\right)&=&1480&& \\ \\
    5000r&+&7333.33r&=&1480&& \\ \\
    &&\dfrac{12333.33r}{12333.33}&=&\dfrac{1480}{12333.33}&& \\ \\
    &&r&=&0.12&=&12\% \\ \\
    &&\dfrac{2}{3}r&=&0.08&=&8\%
    \end{array}\)
  23. \(\begin{array}{rrrrrrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &&5n&+&10d&+&25q&=&510&& \\
    &&&&&&n&=&2d&& \\
    &&&&&&q&=&d&-&3 \\ \\
    5(2d)&+&10d&+&25(d&-&3)&=&510&& \\
    10d&+&10d&+&25d&-&75&=&510&& \\
    &&&&&+&75&&+75&& \\
    \hline
    &&&&&&\dfrac{45d}{45}&=&\dfrac{585}{45}&& \\ \\
    &&&&&&d&=&13&& \\ \\
    &&&&&&n&=&2(13)&& \\
    &&&&&&n&=&26&& \\ \\
    &&&&&&q&=&13&-&3 \\
    &&&&&&q&=&10&&
    \end{array}\)
  24. \(\begin{array}{rr}
    \\ \\ \\
    \begin{array}{rrrrrcrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &5n&+&10d&+&25q&=&375 \\
    &n&+&d&+&q&=&40 \\
    &&&&&d&=&3q \\ \\
    &(n&+&d&+&q&=&40)(-5) \\
    &-5n&-&5d&-&5q&=&-200 \\
    +&5n&+&10d&+&25q&=&375 \\
    \hline
    &&&&&\dfrac{5d+20q}{5}&=&\dfrac{175}{5} \\ \\
    &&&d&+&4q&=&35 \\
    &&&3q&+&4q&=&35 \\
    &&&&&\dfrac{7q}{7}&=&\dfrac{35}{7} \\ \\
    &&&&&q&=&5 \\ \\
    \end{array}
    &\hspace{0.25in}
    \begin{array}{rrrrrrr}
    \\ \\ \\ \\
    &&&&d&=&3(5) \\
    &&&&d&=&15 \\ \\
    n&+&d&+&q&=&40 \\
    n&+&15&+&5&=&40 \\
    &&n&+&20&=&40 \\
    &&&-&20&&-20 \\
    \hline
    &&&&n&=&20
    \end{array}
    \end{array}\)
  25. \(\begin{array}{rrrrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &&&&S_{22}&=&3&+&4S_{40} \\
    &&22S_{22}&+&40S_{40}&=&834&& \\ \\
    22(3&+&4S_{40})&+&40S_{40}&=&834&& \\
    66&+&88S_{40}&+&40S_{40}&=&834&& \\
    -66&&&&&&-66&& \\
    \hline
    &&&&\dfrac{128S_{40}}{128}&=&\dfrac{768}{128}&& \\ \\
    &&&&S_{40}&=&6&& \\ \\
    &&&&S_{22}&=&3&+&4(6) \\
    &&&&S_{22}&=&3&+&24 \\
    &&&&S_{22}&=&27&&
    \end{array}\)

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.