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Answer Key 5.2

  1. \(\begin{array}{rrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\
    -3x&=&6x&-&9 \\
    -6x&&-6x&& \\
    \hline
    \dfrac{-9x}{-9}&=&\dfrac{-9}{-9}&& \\ \\
    x&=&1&& \\ \\
    \therefore y&=&-3(1)&& \\
    y&=&-3&& \\ \\
    (1,-3)&&&&
    \end{array}\)
  2. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    x&+&5&=&-2x&-&4 \\
    +2x&-&5&&+2x&-&5 \\
    \hline
    &&\dfrac{3x}{3}&=&\dfrac{-9}{3}&& \\ \\
    &&x&=&-3&& \\ \\
    &&\therefore y&=&-3&+&5 \\
    &&y&=&2&& \\ \\
    (-3,2)&&&&&& \\
    \end{array}\)
  3. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    2x&-&1&=&-2x&-&9 \\
    +2x&+&1&&+2x&+&1 \\
    \hline
    &&\dfrac{4x}{4}&=&\dfrac{-8}{4}&& \\ \\
    &&x&=&-2&& \\ \\
    &&\therefore y&=&2(-2)&-&1 \\
    &&y&=&-4&-&1 \\
    &&y&=&-5&& \\
    (-2,-5)&&&&&&
    \end{array}\)
  4. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\
    6x&+&3&=&-6x&+&3 \\
    +6x&-&3&&+6x&-&3 \\
    \hline
    &&\dfrac{12x}{12}&=&\dfrac{0}{12}&& \\ \\
    &&x&=&0&& \\ \\
    &&\therefore y&=&6(0)&+&3 \\
    &&y&=&3&& \\
    (0,3)&&&&&&
    \end{array}\)
  5. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    6x&+&4&=&-3x&-&5 \\
    +3x&-&4&&+3x&-&4 \\
    \hline
    &&\dfrac{9x}{9}&=&\dfrac{-9}{9}&& \\ \\
    &&x&=&-1&& \\ \\
    &&\therefore y&=&6(-1)&+&4 \\
    &&y&=&-6&+&4 \\
    &&y&=&-2&& \\
    (-1,-2)&&&&&&
    \end{array}\)
  6. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    3x&+&13&=&-2x&-&22 \\
    +2x&-&13&&+2x&-&13 \\
    \hline
    &&\dfrac{5x}{5}&=&\dfrac{-35}{5}&& \\ \\
    &&x&=&-7&& \\ \\
    &&\therefore y&=&3(-7)&+&13 \\
    &&y&=&-21&+&13 \\
    &&y&=&-8&& \\
    (-7,-8)&&&&&&
    \end{array}\)
  7. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    3x&+&2&=&-3x&+&8 \\
    +3x&-&2&&+3x&-&2 \\
    \hline
    &&\dfrac{6x}{6}&=&\dfrac{6}{6}&& \\ \\
    &&x&=&1&& \\ \\
    &&\therefore y&=&3(1)&+&2 \\
    &&y&=&3&+&2 \\
    &&y&=&5&& \\
    (1,5)&&&&&&
    \end{array}\)
  8. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    -2x&-&9&=&-5x&-&21 \\
    +5x&+&9&&+5x&+&9 \\
    \hline
    &&\dfrac{3x}{3}&=&\dfrac{-12}{3}&& \\ \\
    &&x&=&-4&& \\ \\
    &&\therefore y&=&-2(-4)&-&9 \\
    &&y&=&8&-&9 \\
    &&y&=&-1&& \\
    (-4,-1)&&&&&&
    \end{array}\)
  9. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    2x&-&3&=&-2x&+&9 \\
    +2x&+&3&&+2x&+&3 \\
    \hline
    &&\dfrac{4x}{4}&=&\dfrac{12}{4}&& \\ \\
    &&x&=&3&& \\ \\
    &&\therefore y&=&2(3)&-&3 \\
    &&y&=&6&-&3 \\
    &&y&=&3&& \\
    (3,3)&&&&&&
    \end{array}\)
  10. \(\begin{array}{rrrrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    7x&-&24&=&-3x&+&16 \\
    +3x&+&24&&+3x&+&24 \\
    \hline
    &&\dfrac{10x}{10}&=&\dfrac{40}{10}&& \\ \\
    &&x&=&4&& \\ \\
    &&\therefore y&=&7(4)&-&24 \\
    &&y&=&28&-&24 \\
    &&y&=&4&& \\
    (4,4)&&&&&&
    \end{array}\)
  11. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    3x&-&3(3x&-&4)&=&-6 \\
    3x&-&9x&+&12&=&-6 \\
    &&&-&12&&-12 \\
    \hline
    &&&&\dfrac{-6x}{-6}&=&\dfrac{-18}{-6} \\ \\
    &&&&x&=&3 \\ \\
    &&&&\therefore y&=&3(3)-4 \\
    &&&&y&=&9-4 \\
    &&&&y&=&5 \\
    (3,5)&&&&&&
    \end{array}\)
  12. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    -x&+&3(6x&+&21)&=&\phantom{-}12 \\
    -x&+&18x&+&63&=&\phantom{-}12 \\
    &&&-&63&&-63 \\
    \hline
    &&&&\dfrac{17x}{17}&=&\dfrac{-51}{17} \\ \\
    &&&&x&=&-3 \\ \\
    &&&&\therefore y&=&6(-3)+21 \\
    &&&&y&=&-18+21 \\
    &&&&y&=&3 \\
    (-3,3)&&&&&&
    \end{array}\)
  13. \(\begin{array}{rrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\
    3x&-&6(-6)&=&30 \\
    3x&+&36&=&30 \\
    &-&36&&-36 \\
    \hline
    &&\dfrac{3x}{3}&=&\dfrac{-6}{3} \\ \\
    &&x&=&-2 \\ \\
    &&y&=&-6 \\
    (-2,-6)&&&& \\
    \end{array}\)
  14. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    6x&-&4(-6x&+&2)&=&-8 \\
    6x&+&24x&-&8&=&-8 \\
    &&&+&8&&+8 \\
    \hline
    &&&&\dfrac{30x}{30}&=&\dfrac{0}{30} \\ \\
    &&&&\therefore x&=&0 \\ \\
    &&&&\therefore y&=&-6(0)+2 \\
    &&&&y&=&0+2 \\
    &&&&y&=&2 \\
    (0,2)&&&&&&
    \end{array}\)
  15. \(\begin{array}{rrrrr}
    \\ \\ \\ \\ \\ \\ \\ \\ \\
    3x&+&4(-5)&=&-17 \\
    3x&-&20&=&-17 \\
    &+&20&&+20 \\
    \hline
    &&\dfrac{3x}{3}&=&\dfrac{3}{3} \\ \\
    &&x&=&1 \\ \\
    &&y&=&-5 \\
    (1,-5)&&&& \\
    \end{array}\)
  16. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    7x&+&2(5x&+&5)&=&-7 \\
    7x&+&10x&+&10&=&-7 \\
    &&&-&10&&-10 \\
    \hline
    &&&&\dfrac{17x}{17}&=&\dfrac{-17}{17} \\ \\
    &&&&x&=&-1 \\ \\
    &&&&\therefore y&=&5(-1)+5 \\
    &&&&y&=&-5+5 \\
    &&&&y&=&0 \\
    (-1,0)&&&&&&
    \end{array}\)
  17. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    -6x&+&6y&=&-12&(\div &6) \\
    -x&+&y&=&-2&& \\
    +x&&&&+x&& \\
    \hline
    &&y&=&x&-&2 \\ \\
    8x&-&3(x&-&2)&=&16 \\
    8x&-&3x&+&6&=&16 \\
    &&&-&6&&-6 \\
    \hline
    &&&&\dfrac{5x}{5}&=&\dfrac{10}{5} \\ \\
    &&&&x&=&2 \\ \\
    &&&&\therefore y&=&x-2 \\
    &&&&y&=&2-2=0 \\
    (2,0)&&&&&&
    \end{array}\)
  18. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    -8x&+&2y&=&-6&(\div &2) \\
    -4x&+&y&=&-3&& \\
    +4x&&&&+4x&& \\
    \hline
    &&y&=&4x&-&3 \\ \\
    -2x&+&3(4x&-&3)&=&11 \\
    -2x&+&12x&-&9&=&11 \\
    &&&+&9&&+9 \\
    \hline
    &&&&\dfrac{10x}{10}&=&\dfrac{20}{10} \\ \\
    &&&&x&=&2 \\ \\
    &&&&\therefore y&=&4(2)-3 \\
    &&&&y&=&8-3=5 \\
    (2,5)&&&&&&
    \end{array}\)
  19. \(\begin{array}{rrrrrrl}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    -7x&-&y&=&20&& \\
    -20&+&y&&-20&+&y \\
    \hline
    -7x&-&20&=&y&& \\ \\
    2x&+&3(-7x&-&20)&=&\phantom{+}16 \\
    2x&-&21x&-&60&=&\phantom{+}16 \\
    &&&+&60&&+60 \\
    \hline
    &&&&\dfrac{-19x}{-19}&=&\dfrac{76}{-19} \\ \\
    &&&&x&=&-4 \\ \\
    &&&&\therefore y&=&-7(-4)-20 \\
    &&&&y&=&28-20 \\
    &&&&y&=&8 \\
    (-4,8)&&&&&&
    \end{array}\)
  20. \(\begin{array}{rrrrrrrll}
    \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\
    &&(-x&-&4y&=&-14)&(-1)& \\
    &&x&+&4y&=&14&& \\
    &&&-&4y&&-4y&& \\
    \hline
    &&&&x&=&14&-&4y \\ \\
    &&(-6x&+&8y&=&12)&\div &2 \\
    &&-3x&+&4y&=&6&& \\
    -3(14&-&4y)&+&4y&=&6&& \\
    -42&+&12y&+&4y&=&6&& \\
    +42&&&&&&+42&& \\
    \hline
    &&&&\dfrac{16y}{16}&=&\dfrac{48}{16}&& \\ \\
    &&&&y&=&3&& \\ \\
    &&&&x&=&14&-&4(3) \\
    &&&&x&=&14&-&12 \\
    &&&&x&=&2&& \\
    (2,3)&&&&&&&&
    \end{array}\)

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.