"

Answer Key 2.1

  1.  \(\begin{array}{rrl}
    \\ \\
    v+9&=&16 \\
    -9&&-9 \\
    \hline
    v&=&7
    \end{array}\)
  2. \(\begin{array}{rrrrr}
    \\ \\
    14&=&b&+&3 \\
    -3&&&-&3 \\
    \hline
    11&=&b&&
    \end{array}\)
  3. \(\begin{array}{rrrrr}
    \\ \\
    x&-&11&=&-16 \\
    &+&11&&+11 \\
    \hline
    &&x&=&-5
    \end{array}\)
  4. \(\begin{array}{rrrrr}
    \\ \\
    -14&=&x&-&18 \\
    +18&&&+&18 \\
    \hline
    x&=&4&&
    \end{array}\)
  5. \(\begin{array}{rrrrr}
    \\ \\
    30&=&a&+&20 \\
    -20&&&-&20 \\
    \hline
    a&=&10&&
    \end{array}\)
  6. \(\begin{array}{rrrrr}
    \\ \\
    -1&+&k&=&5 \\
    +1&&&&+1 \\
    \hline
    &&k&=&6
    \end{array}\)
  7. \(\begin{array}{rrrrr}
    \\ \\
    x&-&7&=&-26 \\
    &+&7&&+7 \\
    \hline
    &&x&=&-19
    \end{array}\)
  8. \(\begin{array}{rrrrr}
    \\ \\
    -13&+&p&=&-19 \\
    +13&&&&+13 \\
    \hline
    &&p&=&-6
    \end{array}\)
  9. \(\begin{array}{rrrrr}
    \\ \\
    13&=&n&-&5 \\
    +5&&&+&5 \\
    \hline
    n&=&18&&
    \end{array}\)
  10. \(\begin{array}{rrrrr}
    \\ \\
    22&=&16&+&m \\
    -16&&-16&& \\
    \hline
    m&=&6&&
    \end{array}\)
  11. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{340}{-17}&=&\dfrac{-17x}{-17} \\ \\
    x&=&-20
    \end{array}\)
  12. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{4r}{4}&=&\dfrac{-28}{4} \\ \\
    r&=&-7
    \end{array}\)
  13. \(\begin{array}{l}
    \\ \\
    \left(-9=\dfrac{n}{12}\right)(12) \\ \\
    n=-108
    \end{array}\)
  14. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{27}{9}&=&\dfrac{9b}{9} \\ \\
    b&=&3
    \end{array}\)
  15. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{20v}{20}&=&\dfrac{-160}{20} \\ \\
    v&=&-8
    \end{array}\)
  16. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{-20x}{-20}&=&\dfrac{-80}{-20} \\ \\
    x&=&4
    \end{array}\)
  17. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{340}{20}&=&\dfrac{20n}{20} \\ \\
    n&=&17
    \end{array}\)
  18. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{12}{8}&=&\dfrac{8a}{8} \\ \\
    a&=&\dfrac{3}{2}
    \end{array}\)
  19. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{16x}{16}&=&\dfrac{320}{16} \\ \\
    x&=&20
    \end{array}\)
  20. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{8k}{8}&=&\dfrac{-16}{8} \\ \\
    k&=&-2
    \end{array}\)
  21. \(\begin{array}{rrrrr}
    \\ \\
    -16&+&n&=&-13 \\
    +16&&&&+16 \\
    \hline
    &&n&=&3
    \end{array}\)
  22. \(\begin{array}{rrrrr}
    \\ \\
    -21&=&x&-&5 \\
    +5&&&+&5 \\
    \hline
    x&=&-16&&
    \end{array}\)
  23. \(\begin{array}{rrrrr}
    \\ \\
    p&-&8&=&-21 \\
    &+&8&&+8 \\
    \hline
    &&p&=&-13
    \end{array}\)
  24. \(\begin{array}{rrrrr}
    \\ \\
    m&-&4&=&-13 \\
    &+&4&&+4 \\
    \hline
    &&m&=&-9
    \end{array}\)
  25. \(\begin{array}{l}
    \\ \\
    \left(\dfrac{r}{14}=\dfrac{5}{14}\right)(14) \\ \\
    r=5
    \end{array}\)
  26. \(\begin{array}{l}
    \\ \\
    \left(\dfrac{n}{8}=40\right)(8) \\ \\
    n=320
    \end{array}\)
  27. \(\begin{array}{rrl}
    \\ \\ \\
    \dfrac{20b}{20}&=&\dfrac{-200}{20} \\ \\
    b&=&-10
    \end{array}\)
  28. \(\begin{array}{l}
    \\ \\ \\ \\
    \left(-\dfrac{1}{3}=\dfrac{x}{12}\right) (12) \\ \\
    -\dfrac{1}{3}\cdot 12 = x \\
    \phantom{-\dfrac{1}{3}\cdot 1}x=-4
    \end{array}\)

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.