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Answer Key 6.7

  1. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{20x^4}{4x^3}&+&\dfrac{x^3}{4x^3}&+&\dfrac{2x^2}{4x^3} \\ \\
    5x&+&\dfrac{1}{4}&+&\dfrac{1}{2x}
    \end{array}\)
  2. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{5x^4}{9x}&+&\dfrac{45x^3}{9x}&+&\dfrac{4x^2}{9x} \\ \\
    \dfrac{5}{9}x^3&+&5x^2&+&\dfrac{4}{9}x
    \end{array}\)
  3. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{20n^4}{10n}&+&\dfrac{n^3}{10n}&+&\dfrac{40n^2}{10n} \\ \\
    2n^3&+&\dfrac{n^2}{10}&+&4n
    \end{array}\)
  4. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{3k^3}{8k}&+&\dfrac{4k^2}{8k}&+&\dfrac{2k}{8k} \\ \\
    \dfrac{3}{8}k^2&+&\dfrac{k}{2}&+&\dfrac{1}{4}
    \end{array}\)
  5. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{12x^4}{6x}&+&\dfrac{24x^3}{6x}&+&\dfrac{3x^2}{6x} \\ \\
    2x^3&+&4x^2&+&\dfrac{x}{2}
    \end{array}\)
  6. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{5p^4}{4p}&+&\dfrac{16p^3}{4p}&+&\dfrac{16p^2}{4p} \\ \\
    \dfrac{5}{4}p^3&+&4p^2&+&4p
    \end{array}\)
  7. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{10n^4}{10n^2}&+&\dfrac{50n^3}{10n^2}&+&\dfrac{2n^2}{10n^2} \\ \\
    n^2&+&5n&+&\dfrac{1}{5}
    \end{array}\)
  8. \(\begin{array}{ccccc}
    \\ \\ \\
    \dfrac{3m^4}{9m^2}&+&\dfrac{18m^3}{9m^2}&+&\dfrac{27m^2}{9m^2} \\ \\
    \dfrac{m^2}{3}&+&2m&+&3
    \end{array}\)
  9. \(\enclose{longdiv}{45x^2 + 56x + 16} {9x + 4}\)
  10. \((6x^2+16x+16) \div (6x-2)\hspace{0.5in} \text{ or } x+3+\dfrac{22}{6x-2}\)
  11. \((10x^2 - 32x + 6) \div (10x - 2)\)
  12. \((x^2 + 7x + 12) \div (x + 4)\)
  13. \((4x^2 - 33x + 35) \div (4x - 5)\)
  14. \((4x^2 - 23x - 35) \div (4x + 5)\)
  15. \((x^3 + 15x^2 + 49x - 49) \div (x + 7)\)
  16. \((6x^3 - 12x^2 - 43x - 20) \div (x - 4)\)
  17. \((x^3 - 6x - 40) \div (x+4) \hspace{0.5in} \text{ or } x^2 - 4x + 10 - \dfrac{80}{x+4}\)
  18. \((x^3 - 16x^2 + 512) \div (x-8)\)
  19. \((x^3 - x^2 - 8x - 16) \div (x-4)\)
  20. \((2x^3 + 6x^2 + 4x + 12) \div (2x + 6)\)
  21. \((12x^3 + 12x^2 - 15x - 9) \div (2x + 3)\)
  22. \((4x^3 - 21x^2 + 6x + 18) \div (4x + 3)\)

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Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.