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Answer Key 9.11

First, the roots:

\begin{tabular}{|c|c|c|} 
\hline 
\begin{array}{ccc}&3& \\ &\textbf{44}& \\ 8&&4\end{array}& 
\begin{array}{ccc}&9& \\ &\textbf{32}& \\ 7&&2\end{array}& 
\begin{array}{ccc}&8& \\ &\textbf{75}& \\ 7&&\sqrt{x} \end{array}\\ 
\hline 
\end{tabular}

Check for pattern in the first box:

  1. 38+4=28
  2. 483=35
  3. (8+3)4=44

Check #3 pattern with the next box:

(7+9)2=32

Finally:

\begin{array}{rrl} (7+8)\sqrt{x}&=&75 \\ \\ 15\sqrt{x}&=&75 \\ \\ \dfrac{15}{15}\sqrt{x}&=&\dfrac{75}{15} \\ \\ \sqrt{x}&=&5 \\ \\ \therefore (\sqrt{x})^2&=&(5)^2 \\ \\ x&=&25 \end{array}

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Intermediate Algebra (Convert to MathJax) Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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